If sin a = 4/5 and sin b = 5 /13 , the find cot(a-b)
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hey, mate here is ur Ans
Cot(a-b)=Cot(a).Cot(b)+1/Cot(b)-Cot(a)
we know that Cot(a)=Cos(a)/Sin(a)
We also know sin^2(a)+cos^2(a)=1
=>Cos(a)=3/5
similarly Cos(b)=12/13
=>Cot(b)=12/5 and cot(a)=3/4
Cot(a-b)=56/33
Cot(a-b)=Cot(a).Cot(b)+1/Cot(b)-Cot(a)
we know that Cot(a)=Cos(a)/Sin(a)
We also know sin^2(a)+cos^2(a)=1
=>Cos(a)=3/5
similarly Cos(b)=12/13
=>Cot(b)=12/5 and cot(a)=3/4
Cot(a-b)=56/33
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