Question

if sin A =4/5 find the value of sinA-cotA/2tanA​

Answer 1

Step-by-step explanation:

sin A = 4/5 = Opposite side/Hypotenuse

Let common ratio be 'k'

Therefore

Opposite side = 4k

Hypotenuse = 5k

According to Pythagoras Theorem

(Adjacent side)² = (Hypotenuse)² - (Opposite side)²

Adjacent side = √((5k)² - (4k)²)

Adjacent side = 3k

Now,

cot A = Adjacent side/Opposite side

cot A = 3k/4k

cot A = 3/4

&

tan A =1/(cot A)

or, tan A = 4/3

Substituting in question, we get

((4/5) - (3/4))/2(4/3)

=> ((16 - 15)/20)/(8/3)

=> (1/20)/(8/3)

=> 3/160

Answer 2

Answer:

Hope it's help ..

Step-by-step explanation:

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