Question

if sin A =4\5 than find cosA and TanA​

Answer 1

Answer:

The answer is easy please follow these steps:_

Step-by-step explanation:

given sin A=4/5

so cosA=3/5

so tan A=sin A/cos A=4/5*5/3=4/3

I hope this will help you thank you.

Answer 2

If sin A = 4/5 then,

$cos\ A = \frac{3}{5} \text{ and } tan\ A = \frac{4}{3}$

Solution:

Given that,

$sin\ A = \frac{4}{5}$

We know,

$sin\ theta = \frac{opposite}{hypotenuse}$

Thus,

opposite = 4

hypotenuse = 5

Use pythagoras theorem,

$hypotenuse^2 = opposite^2 + adjacent^2\\\\5^2 = 4^2 + adjacent^2\\\\adjacent^2 = 25 - 16\\\\adjacent^2 = 9\\\\adjacent = 3$

Find cos A

$cos\ A = \frac{adjacent}{hypotenuse}\\\\cos\ A = \frac{3}{5}$

Find tan A

$tan\ A = \frac{opposite}{adjacent} \\\\tan\ A = \frac{4}{3}$

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