If sin A = 4/5 then Cos A= help me in this sum please
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Answer:
cosA=3/5
Step-by-step explanation:
sinA=4/5
make a triangle with hypotenuse 5x and side opp. to angle theta=4
by Pythagoras theorem
3rd side=√25-16
=√9
=3
therefore,
cos (theta)=adjacent side/hypotenuse
=3/5
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EXPLANATION.
⇒ sin(A) = 4/5.
As we know that,
⇒ sinθ = Perpendicular/Hypotenuse.
⇒ sinθ = p/h = 4/5.
By using Pythagoras theorem, we get.
⇒ H² = P² + B².
Hypotenuse > Perpendicular > Base.
Using this formula in the equation, we get.
⇒ (5)² = (4)² + B².
⇒ 25 = 16 + B².
⇒ 25 - 16 = B².
⇒ 9 = B².
⇒ B = √9.
⇒ B = 3.
⇒ cosθ = Base/Hypotenuse.
⇒ cos(A) = 3/5.
MORE INFORMATION.
(1) sin²θ + cos²θ = 1.
(2) 1 + tan²θ = sec²θ.
(3) 1 + cot²θ = cosec²θ.
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