Question

if sin a = 5/13 find cos a what is answer ​

Answer 1

Answer:

sin A =5/13 i.e. opp/hypo

Step-by-step explanation:

AC=13 i.e hypo

BC=5 i.e opp

SO, by Pythagoras thereom

AC sq = BCsq + ABsq

13sq= 5sq+ABsq

169= 25+ABsq

169-25=ABsq

144= ABsq

12=AB

hereby, adj = 12

cosA= adj/hypo

12/13

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Answer 2

Answer:

cos a=12/13

Step-by-step explanation:

SinA= opposite side

hypotenuse

IF SinA= 5

13

then,

5 = opposite side

13 = hypotenuse

NOW,

CosA= adjacent side

hypotenuse

We know that hypotenuse=13 and,

Adjacent side can be found by using pythagoras

theorem i.e a^2+b^2=c^2 with a=Adjacent side

b=5 and c=13

We get adjacent side=12

We know that CosA= adjacent side

hypotenuse

Hence,

CosA= 12

13