If sin A = 5/13 in a ∆ABC right angled at B then the value of tan C=
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since it was right angled at B,
sin A = opp/hyp = BC/AC = 5/13
by phythagoreus rule
AC² = AB² + BC²
13²=AB²+5²
=> 169 = AB²+25
=> AB² = 169-25 = 144
=> AB = 12
so, tan C = opp/adj = AB/BC = 12/5
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