if sin A=-5/13 ,π<A<3π and cosB = 3/2,3π/2<B<2π find Sina+b. cos a-b tan a+b
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Answered by
1
Answer:
find in maths papa
Step-by-step explanation:
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Answered by
2
As
sin
A
is negative and is in
Q
3
,
cos
A
is negative and
cos
A
=
−
√
1
−
(
−
5
13
)
2
=
−
√
1
−
25
169
=
−
√
144
169
=
−
12
13
Further,
cos
B
is positive and is in
Q
4
,
sin
B
is negative and
sin
B
=
−
√
1
−
(
24
25
)
2
=
−
√
1
−
576
625
=
−
√
49
625
=
−
7
25
Hence
sin
(
A
+
B
)
=
sin
A
cos
B
×
cos
A
sin
B
=
−
5
13
×
24
25
+
(
−
12
13
)
×
(
−
7
25
)
=
−
120
325
+
84
325
=
−
36
325
hope this helps you
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