If sin A = 6/10,find the value of cos A + tan A
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Answer:
Step-by-step explanation:
sinA=6/10
hypotenuse=10
opp side=6
adjacent side=y
by pythagoras theorom
10^2=6^2+y^2
100-36=y^2
64=y^2
y=8
cosA+tanA
8/10+6/8
4/5+3/4
16/20+15/20
hence cosA+tanA=31/20
Thanks
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