Question

if sin A= 60/61, find. the value of tan A sec A​

Answer 1

Answer:

Here, TanA.SecA=3660/121

Step-by-step explanation:

Here, According to question,

sinA=60/61

And as it considered,

=sinA=60/61=P/h(Perpendicular/hypotenuse)

Now, by appyling pythagorean theorem,

=H^2=P^2+B^2

=(61)^2=(60)^2+B^2

=B^2=(61)^2-(60)^2

=B^2=3721-3600

=B^2=121

Now, by doing square root on both sides, we get,

=B=11

Now, as per question,

=TanA=P/b=60/11

=SecA=H/b=61/11

Now, =tanA.secA=60/11×61/11

=3660/121 (Answer)

Thank you.

Answer 2

Answer:

sinA=60/61

And as it considered,

=sinA=60/61=P/h(Perpendicular/hypotenuse)

Now, by appyling Pythagorous  theorem,

=H^2=P^2+B^2

=(61)^2=(60)^2+B^2

=B^2=(61)^2-(60)^2

=B^2=3721-3600

=B^2=121

Now, by doing square root on both sides, we get,

B=11

Now, as per question,

=TanA=P/b=60/11

=SecA=H/b=61/11

Now, =tanA.secA=60/11×61/11

=3660/121

Step-by-step explanation:

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