Question

if sin A=8/11, find the value of sec^2A-tan^2A cot^2A-cosec^2A+1 please.. only answer if you know the answer..​

Answer 1

Step-by-step explanation:

sinA =8/11 =p/h

so, p=8 and h=11

b=root over of h^2‐p^2 =root57

sec^2A ‐tan^2A cot^2A‐cosec^2A +1

=(h/b)^2‐(p/b)^2(b/p)^2‐(h/p)^2 +1

=(121/57‐64/57)(57/64‐121/64)

=1×(‐1)