Question

If sin A = 8/13, find AB.

THE ANSWER IS NOT 13
IT IS
104/ √105

Answer 1

Step-by-step explanation:

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Answer 2

Concept:-

It might resemble a word or a number representation of the quantity's arithmetic value. It could resemble a word or a number that represents the numerical value of the quantity. It could have the appearance of a word or a number that denotes the quantity's numerical value. It could look like a word or a number portrayal of the amount's math esteem. It could look like a word or a number that addresses the mathematical worth of the amount. It could resemble a word or a number that means the amount's mathematical worth.

Given:-

We have been given that If sin A$= 8/13$.

Find:-

We have to find that the value of $AB$.

Solution:-

$sin A = 8/13$

$AB=13x\\BC=P=8x\\AC=\sqrt{105}x$

According to the given question, we get

$(13x)^2-(8x)^2=AB$

Squaring on both the sides

$P^2=105x^2\\P=\sqrt{105x^2}\\P=\sqrt{105}x\\8=\sqrt{105}x$$8^2=\sqrt{105^2}x^2\\64=105x^2\\x^2=\frac{64}{105}\\x=\frac{8}{\sqrt{105}}$

Finding the value of $AB$,

$AB=13 \times \frac{8}{\sqrt{105}}=\frac{104}{\sqrt{105}}$

Hence, the value of $AB$ is $\frac{104}{\sqrt{105}}$.

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