If Sin A=8/17 and A is acute, then cot A=?
Answers
Answered by
14
Heya used theta instead of A
Sin theta=8/17
Cos theta=( 1-sin^2 theta)1/2
Solving we get ...
Cos theta=15/17
Cot theta=cos theta/sin theta
15/17÷17/8
=15/8
@skb
Answered by
4
sin theta =8/17
cos theta=(1-sin²theta) 1/2
then,
cos theta=15/17
cos theta =cos theta/sin theta
15/17÷17/18=15/8
cos theta=(1-sin²theta) 1/2
then,
cos theta=15/17
cos theta =cos theta/sin theta
15/17÷17/18=15/8
Similar questions