If sin A = 8/17 and A is acute, then cot A is equal to : (a) 15/8 (b) 15/17 (c) 8/15 (d) 17/8
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ans :-15/8
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Answer:
Correct option is
A
158
Given, cosA= 178
⇒cos2A+sin2A=1
⇒sin2A=1−cos2A
⇒sin2A=1−(178)2
⇒sin2A=1−28964
⇒sin2A=289289−64
⇒sinA=289225
⇒sinA=1715
Therefore, we know
cotA=sinAcosA
=1715178
=
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