Question

) If Sin(A-8) = ½ , Cos(A+B) = ½, 0 < A+B < 90 , A>B. Find <A and <B​

Answer 1

Answer

angle A = 38°

angle B = 22°

Explanation

Answer 2

Step-by-step explanation:

$sin(A - 8) = \frac{1}{2} \\ = > sin(A - 8) = sin30 \\ = > A - 8 = 30 \\ = > A = 38$

$cos(A+B) = \frac{1}{2} \\ = > cos(A+B) = cos60 \\ = > A+B = 60 \\ = > 38 +B = 60 \\ = > B = 60 - 38 \\ = > B = 22$