Question

if sin a = 9/14 the find the values of cos a and tan a

Answer 1

Answer:

Step-by-step explanation:

Sin A = Opp. side/ Hypotenuse = 9/41 ,

by using Pythagoras theorem,

a²+b² = c² ,

(9)² + b² = (14)² ,

b² = 196-81 ,

b² = 115,

b = √115,

b=10.7.

Cos A = Adj./Hyp. = 10.7/414,

Tan A = Opp./Adj. = 9/10.7 .

Hope it helps you.

Answer 2

Sin a = Height/Hypotenuse = P/H = 9/14

suppose In a Right angle triangle ; Height (P)= 9, Hypotenuse ( H) = 14. So Base (B) = √[(Hypotenuse)² - (Height)² ] = 10.72

Now, Cos a = B/H = 10.72 / 14 = 0.765

and, tan a = P/B = 9/10.72 = 0.839.

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