Question

If sin A =( a^2 - b^2) /(a^2 + b^2)
then find 1+ tan A cosA
​

Answer 1

Step-by-step explanation:

We have,

$\sin( \theta) = \frac{ {a}^{2} - {b}^{2} }{ {a}^{2} + {b}^{2} }$

Now,

$1 + \tan(\theta) \cos(\theta) = 1 + \sin(\theta) = 1 + \frac{ {a}^{2} - {b}^{2} }{ {a}^{2} + {b}^{2} }$

$= \frac{2 {a}^{2} }{ {a}^{2} + {b}^{2} }$