Question

if sin A = a/b then find sec A + tan A in term of a and b

Answer 1

Sin A=a/b=Opposite/Hypotenuse.=BC/AC.

AC^2=AB^2+BC^2

b^2=AB^2+a^2.

AB^2=a^2-b^2.

Tan A = Opposite /Adjacent=a/a^2+b.

SecA= Hypotenuse/Adjacent=b/a^2+b^2.

Therefore,

Sec A +Tan A

=a+b/a^2+b^2.

=1/a+b.

Hope it helps u...
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Answer 2

Answer:

The answer is given below :

sinθ = a/b

So, secθ = b/√(b² - a²)

and

tanθ = a/√(b² - a²)

Now,

secθ + tanθ

= b/√(b² - a²) + a/√(b² - a²)

= (b + a)/√(b² - a²)