Question

if sinθ = a/√ (a²+b² ) then tanθ=? *

Answer 1

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Answer 2

Answer:

The answer is given below :

sinθ = a/b

So, secθ = b/√(b² - a²)

and

tanθ = a/√(b² - a²)

Now,

secθ + tanθ

= b/√(b² - a²) + a/√(b² - a²)

= (b + a)/√(b² - a²)

Thank you for your question.

Step-by-step explanation: