if sin(A-B)=0,cos(A+B)=0,0<A+B<_90°, find Aand B
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Answered by
20
sin(a-b)=0
that means a-b= sin0
a=b
cos (a+b)=0
a+b= cos 90
a+b=90
we know a=b
a+a=90
2a=90
a= 90/2
a=45
so b=45
hope it helps!!!
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Answered by
3
Answer:
the above answer is correct
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