Question

If sin (A-B) =0,cos (A+B)=0, 0degree <A+B<90 degree find Aand B​

Answer 1

Answer:

sin(a-b)=0

that means a-b= sin0

a=b

cos (a+b)=0

a+b= cos 90

a+b=90

we know a=b

a+a=90

2a=90

a= 90/2

a=45

so b=45

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Answer 2

Answer:

Step-by-step explanation:

sin0=0,  

A-B=0  ---- 1

cos90=0,

 A+B=90 --- 2

From 1 and 2

2A=90

A=

Substituting in 1

A-B=0

B= $\frac{1}{2}$

Hence A= $\frac{1}{2}$ , B=