Question

If sin(A-B) = 1/2 and 2cos(A+B)=1 find A and B

Answer 1

As we now
sin 30°=1/2
so,
A-B=30°
now, A=30°+B ....1
also
cos 60°=1/2
so, A+B=60° ....2
Putting the equation 1 in 2
so, 30°+B+B=60°
2B=60°-30°
B=30°/2
B=15°
so, A=30°+15°=45°
I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST

Answer 2

Hey here is your answer
=========================
sin(A-B)=1/2
sin(A-B)=sin30° __(sin30°=1/2)
(A-B)=30°------(1)

2cos(A+B)=1
cos(A+B)=1/2 __(cos60°=1/2)
cos(A+B)=cos60°
(A+B)=60°-------(2)

From eq. 1 ,

A-B=30°
A=30°+B

Putting the value of A in eq. 2 ,

(A+B)=60°
30°+B+B=60°
2B=60°-30°
B=30°/2
B=15°

A=30°+B
A=30°+15°
A=45°
===========================
Hope it may helpful to you
plzz mark me as brainlist