Math, asked by khushiacharjee547, 2 months ago

if sin (a-b)=1/2 and cos(a+b)=1/2, 0 degree <A+B ≤ 90 degree ,A>B find A and B​

Answers

Answered by poonamsingh00q1
0

Answer:

by brainliest

Step-by-step explanation:

If sin (A – B) = 1/2, cos(A + B) = 1/2; 0° < A + B < 90°; A > B, find A and B.Read more on Sarthaks.com - https://www.sarthaks.com/929290/if-sin-a-b-1-2-cos-a-b-1-2-0-a-b-90-a-b-find-a-and-b

Answered by udit24singhania
0

Step-by-step explanation:

We know that Sin(a-b) =1/2

So, Sin(a-b) = 30 degree

(a-b) = 30 degree_______(i)

We know that Cos(a+b) =1/2

So, Cos(a+b) =60 degree

(a+b) = 60 degree_______(ii)

By adding both the equation, we get

2a=90 degree

So, a= 45 degree and b= 15 degree

Hence, verified.

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