Question

if sin (A+B) =1/2 and cos(A-B)=1 FIND A AND B

Answer 1

$\sin(x + y) = \frac{1}{2} \\ x + y = \frac{\pi}{6}$
x+y=30°

$\cos(x - y) = 1 = x - y = 0$
x-y=0

adding both equation.....

2x=30

x=15°

so Y=15°.

hope it will help you.

Answer 2

hey dear
irfan is here,

as we know that sin 30degree=1/2
so
sin(a+b)=30
cos(a-b)=o degree (cos 90-theta)=sin theta
here,
a+b=30...1
a-b=0.......2
=2a=30
a=15
put a=15 in ..1
a+b=30
15+b=30
b=30-15=15