If sin (A – B) = 1/2,
cos (A + B) = 1/2,
0° < A + B ≤ 90°,
A > B,
find A and B.
kaulsaiesh:
one more equation is nesecer
sorry necessary*
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sin(A-B)=sin30 { ..sin1\2 = 30 }
cos (A+B) =cos 90 {since cos 1\2=90}
A-B=30.....................1
A+B=90....................2
FROM Eq 1 and 2 we have ;
A-B=30
A+B=90
2A=120
A=60
SUBTITUTE THE VALUE OF A IN A-B=30 WE GET ;
60-B=30
-B=30-60
-B=-30
B=30
ANS = A=60 B=30
cos (A+B) =cos 90 {since cos 1\2=90}
A-B=30.....................1
A+B=90....................2
FROM Eq 1 and 2 we have ;
A-B=30
A+B=90
2A=120
A=60
SUBTITUTE THE VALUE OF A IN A-B=30 WE GET ;
60-B=30
-B=30-60
-B=-30
B=30
ANS = A=60 B=30
You sure of your answer? (Because, I don't know what actually the answer is)
yaa...i am sure ...
Thank you :)
ur wlcm.....
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