if sin (A-B ),=1/2,COS(A+B),=1/2 THEN FIND THE VALUE OF A AND B
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Sin (A-B) = ½
Sin (A-B) = sin 30°
A-B = 30° ---(1)
cos (A+B) = ½
cos (A+B) = cos 60°
A+B = 60° ---(2)
A-B = 30°
A+B = 60°
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2A = 90°
A = 45°
A-B = 30°
45° - B = 30°
B = 45° - 30°
B = 15°
A = 45° and B = 15°
Sin (A-B) = sin 30°
A-B = 30° ---(1)
cos (A+B) = ½
cos (A+B) = cos 60°
A+B = 60° ---(2)
A-B = 30°
A+B = 60°
–––––––
2A = 90°
A = 45°
A-B = 30°
45° - B = 30°
B = 45° - 30°
B = 15°
A = 45° and B = 15°
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