Question

if sin a-b=1/2 , cos a+b= 1/ root 2 ,0 b. then find the value of a & b .

Answer 1

Step-by-step explanation:

Given -

• Sin a - b = 1/2
• Cos a + b = 1/√2

To Find -

• Value of a and b

As we know that :-

• Sin30° = 1/2

It means,

a - b = 30° ..... (i)

And

• Cos45° = 1/√2

It means,

a + b = 45° ... (ii)

Now,

From solving equation (i) and (ii), we get :-

→ a - b = 30°

a + b = 45°

→ 2a = 75°

→ a = 37.5°

And

→ 37.5° + b = 45°

→ b = 45° - 37.5°

→ b = 7.5°

Hence,

The value of a is 37.5° and b is 7.5°.

Answer 2

Answer:

Answer:

• The value of a and b is 37.5° and 7.5°

Given:

• The equations are, Sin(a-b)=1/2 and cos(a+b)=1/√2

To find:

• The value of a and b=?

Solution:

From the above equation,

→sin(a-b)=1/2

→sin(a-b)=sin30°

→a-b=30°

→Cos(a+b)=1/√2

→cos(a+b)=cos 45°

→a+b=45°

Solve the above equations,

2a=75°

a=37.5°

Substitute a value in equation 1

a-b=30°

37.5-b=30°

b=7.5°

Step-by-step explanation:

Hope it helps you......