if sin (A-B) = 1 /2and
cos (A+B)=1/2, where 0 degree is less than A+B less than 90 degree, A is greater than B, find the value of A and B
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Answered by
4
Answer:
Step-by-step explanation:
The Maximum value of Sin x is 1 .
If Sin A+Sin B=2
Then, it must be it's maximum value.
i.e., Sin A=Sin B=1
So, A=B= 90°
Now, Cos A+Cos B
= 2 Cos 90°
= 0
Answered by
6
Answer:sin (A-B) = 1 /2
Sin30°=1/2
Thus (A-B) =30° EQ 1
cos (A+B)=1/2
Cos60°=1/2
This (A+B) =30° EQ 2
Now add EQ 1 and 2
We get A-B+A+B=30+30
2A=60°
A=60/2
A=30°
SUBSTITUTE A VALUE IN EQUATION 1
A-B =30
30-B=39
-B=30-30
-B=0
PLS MARK BRAINLIEST
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