Math, asked by snehakashyap10, 10 months ago

if sin (A-B) = 1 /2and
cos (A+B)=1/2, where 0 degree is less than A+B less than 90 degree, A is greater than B, find the value of A and B

Answers

Answered by rvr7714
4

Answer:

Step-by-step explanation:

The Maximum value of Sin x is 1 .

If Sin A+Sin B=2

Then, it must be it's maximum value.

i.e., Sin A=Sin B=1

So, A=B= 90°

Now, Cos A+Cos B

= 2 Cos 90°

= 0

Answered by aswinrkumar4
6

Answer:sin (A-B) = 1 /2

Sin30°=1/2

Thus (A-B) =30° EQ 1

cos (A+B)=1/2

Cos60°=1/2

This (A+B) =30° EQ 2

Now add EQ 1 and 2

We get A-B+A+B=30+30

2A=60°

A=60/2

A=30°

SUBSTITUTE A VALUE IN EQUATION 1

A-B =30

30-B=39

-B=30-30

-B=0

PLS MARK BRAINLIEST

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