Question

If Sin (A+B) = 1 and cos (A-B) = 1,0 <A+B <90,
A>B .find A and B​

Answer 1

Answer:

Answer:

A = 45° , B = 45°

Explanation:

It is given that,

i) sin(A+B) = 1

=> sin(A+B) = sin90°

=> A+B = 90° ----(1)

ii) cos(A-B) = 1

=> cos(A-B) = cos0°

=> A-B = 0° ----(2)

Add equations (1)&(2), we get

=> A+B+A-B=90°-0°

=> 2A = 90°

=> A = 90°/2

=> A = 45°

Substitute A=45° in equation (1),

we get

45°+B = 90°

=> B = 90° - 45°

=> B = 45°

Therefore,

A = 45° , B = 45°

Step-by-step explanation:

Answer 2

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