Question

if sin(A+B)=1 and cos(A-B) =1, 0<A+B<=90, A>=B, find A and B. ​

Answer 1

Answer:

$A = 45$

$B = 45$

Step-by-step explanation:

To solve this, you must know this:

$sin(90)=1$

$cos(0)=1$

From here, make a system of equation:

$A+B = 90$

$A-B = 0$

Add both of them to get:

$2A = 90$

$A=45$

If A=45, then B is also 45

Answer 2

Answer:

Step-by-step explanation: