Question

if sin(A+B)=1 and cos(A-B)=1,0°<A+B≤90⁰,A≥B
find A and B
plz answer explain
to get the mark of Brainliest​

Answer 1

Step-by-step explanation:

Given :-

Sin(A+B)=1

Cos(A-B)=1,

0°<A+B≤90⁰,A≥B

To find :-

Find the values of A and B ?

Solution :-

Given that

Sin (A+B) = 1

=> Sin ( A+ B) = Sin 90°

A+B = 90° ----------------(1)

and

Cos (A-B) = 1

=> Cos (A-B) = Cos 0°

A-B = 0° ------------(2)

=> A = 0° + B

=> A = B -----------(3)

On Substituting the value of A in (1)

=> B+B = 90°

=> 2B = 90°

=> B = 90°/2

=>B = 45°

=> A = 45°

Answer:-

The value of A = 45°

The value of B = 45°

Check :-

Sin(A+B)

=> Sin (45°+45°)

=>>Sin 90°

=> 1

and

Cos(A-B)

=> Cos (45°-45°)

=> Cos 0°

=> 0

Verified the given relations in the given problem

Used formulae:-

• Sin 90°=1

• Cos 0°=1

Answer 2

Step-by-step explanation:

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