Math, asked by subham7873, 10 months ago

If sin (A+B) = 1 and cos (A-B) = 1,0° <A + B< 90°,A>B find A and B​

Answers

Answered by jnbasha0209
7

Answer:

sin (A + B ) = sin 90°

(A+ B ) = 90° .........(1)

cos (A- B ) = cos 0°

(A - B ) = 0° ........ (2)

by elimination method,

2A = 90°

A = 45°

substitute A = 45° in (1) ,

B = 45°

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