If sin (A+B) = 1 and cos (A-B) = 1,0° <A + B< 90°,A>B find A and B
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Answer:
sin (A + B ) = sin 90°
(A+ B ) = 90° .........(1)
cos (A- B ) = cos 0°
(A - B ) = 0° ........ (2)
by elimination method,
2A = 90°
A = 45°
substitute A = 45° in (1) ,
B = 45°
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