Question

if Sin (A + B) =1 and cos (A-B) =1,0°_<(A+B) _< 90° and A > B then find A and B.​

Answer 1

Step-by-step explanation:

sin (A + B)= 1 or sin (A + B) = sin 90° [As sin 90° = 1]

A + B = 90° …(1)

Again, Cos(A-B) = 1

= cos 0°

A – B = 0 …(2)

Adding (1) and (2), we get

2A = 90° or A = 45°

Putting A = 45° in (1) we get

45° + B = 90° or B = 45°

Hence, A = 45° and B = 45°.