If sin (A+B) =1 and cos (A_B) =1, 0°< or =(A+B)< or =90°and A>B then find A and B.
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Answer:
sin(a+b)=sin90°
a+b=90--------eq.1
cos(a-b)=cos0°
a-b=0-----------eq.2
from eq. 1 and 2
a= 45°
b=45°
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