Question

If sin (A+B)= 1 and cos(A-B) = 1, 0º < A+B <=90°, A>=B find the
values of A and B.​

Answer 1

Hey MATE!

Answer:

A = 45° B= 45°

Step-by-step explanation:

sin(A+ B) = 1

Therefore, A + B = 45°-----1st eqn.

cos (A- B) = 1

Therefore, A - B = 45°------2nd eqn.

Now 1 eqn. + 2nd eqn.

we get 2A = 90

=> A = 45°

=> B = 45°

Hope it helps

Hakuna Matata