Question

if sin (a+b)=1 and cos(a-b) =1/2 and find A and B​

Answer 1

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Answer 2

Answer:

Hello!

Step-by-step explanation:

sin (a+b) = 1

=> sin (a+b) = sin 90degree

=> a+b = 90 degree.........................................(1)

Again, cos(a-b) = 1/2

=> cos (a-b) = cos 60degree

=> a-b = 60 degree...........................................(2)

Now, (1)-(2),we get_

a+b - (a-b) = 90-60

=> a + b - a + b = 30 degree

=> 2b = 30 degree

=> b = 30degree / 2

=> b = 15 degree.

Again putting 'b' in equation (1), we get_

a + b = 90 degree

=> a + 15 = 90 degree

=> a = 90-15 degree

=> a = 75 degree

THEREFORE , a = 75 degree & b = 15 degree.

THANK YOU forthe question. Hope this would be useful to you!