If sin(A+B) = 1 and cos(A-B) = 1 find A and B.
EXPERTS, please explain the solution step by step.
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Answer:
A = 45° , B = 45°
Explanation:
It is given that,
i) sin(A+B) = 1
=> sin(A+B) = sin90°
=> A+B = 90° ----(1)
ii) cos(A-B) = 1
=> cos(A-B) = cos0°
=> A-B = 0° ----(2)
Add equations (1)&(2), we get
=> A+B+A-B=90°-0°
=> 2A = 90°
=> A = 90°/2
=> A = 45°
Substitute A=45° in equation (1),
we get
45°+B = 90°
=> B = 90° - 45°
=> B = 45°
Therefore,
A = 45° , B = 45°
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