Math, asked by varshinimangala123, 6 months ago

If sin (A+B)=1 and cos (A-B)=1 find angle A and angle B​

Answers

Answered by villian2006
0

Answer:

let a and b be as 1x+1x

a+b=180

1x+1x =18080

2x=180

x=180÷2

x=90

a=1×90=90

b=1×90=90

a-b=180

1x+1x=180

,2x=180

x=180÷2

x=90

a =1×90=90

b=1×90=90

Step-by-step explanation:

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Answered by sindhupaila2007
0

Step-by-step explanation:

sin(A+B)=1

sin(A+B)=sin90

A+B=90......1

cos(A-B)=1

cos(A-B)=cos0

A-B=0........2

1+2

A+B=90

A-B=0

A=45

B=45

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