Question

if sin(A-B)=1 and cos(A+B)=1,then the value of A and B, respectively are​

Answer 1

Step-by-step explanation:

sin(A-B)=1

sin(A-B)= sin90

A-B= 90

cos(A+B)= 1

cos(A+B)=cos0

A+B=0

on adding both eq.

2A= 90

A= 45

on subtracting eq1 from eq2

2B= -90

B= -45

hence A=45 B= -45

#666

Answer 2

sin (A - B)= 1 or sin (A - B) = sin 90° [As sin 90° = 1]

A - B = 90° …(1)

Again, Cos(A+B) = 1 = cos 0°

A + B = 0 …(2)

Adding (1) and (2),

we get 2A = 90° or A = 45° Putting A = 45° in (1) we get

45° - B = 90° or B = -45° Hence, A = 45° and B = -45°