Math, asked by Anonymous, 8 months ago

If sin (A+B) = 1 and cos(A-B)=√3/2, 0 B, find A and B

Answers

Answered by Anonymous
20

sin(A+B)=1

cos(A-B)=√3/2

We know sin-¹ =90

A+B=9 _ _ _ _(1)

cos (A-B)=root 3/2

A-B=cos-¹ root 3/2

We know cos-¹ root 3/2=30

A-B=30 _ _ _ _ _ (2)

Solve (1) & (2)

A+B=90

A-B=30 add

2A=120

A=60 B=30 (Ans)

Answered by Anonymous
1

Hi mate,

here's your answer

hope this helps you

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