Question

If sin(A+B)=1 and cos(A−B)=3√2, 0B then find A and B.

Answer 1

Answer:

sin(A+B)=1

Sin(A+B)=sin 90°

(A+B)=90°

cos(A-B) =√3/2

cos (A-B) =cos60°

A-B =60°

A+B+A-B=90°+60°

2A=150°

A=75°

B=15°