If sin(A+B)=1 and cos (A-B)=√3/2 , then find A and B.<br />
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Answered by
12
A+B=90° and A-B=30°;2A=120°;A=60°;B=90-60=30;so,A=60 and B=30
swag69:
wer does the sin and cos go?...they have to get cancelled re?
ohh kk I get it
Answered by
24
sin(A+B) = 1
Sin (A+B)=Sin90°
A+B=90°
Cos(A-B)= √3/2
Cos(A-B)=Cos30°
A-B = 30°
A+B+A-B=90+30
2A=120
A=60°
A-B=30°
B=30°
Sin (A+B)=Sin90°
A+B=90°
Cos(A-B)= √3/2
Cos(A-B)=Cos30°
A-B = 30°
A+B+A-B=90+30
2A=120
A=60°
A-B=30°
B=30°
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