Math, asked by darshanudileepu45, 4 months ago

If sin (A + B) = 1 and cos (A -B) = √3÷2, then find the value of A and B.

Answers

Answered by uvivek9898
1

Answer:

sin(A + B) = 1

sin(A + B) =sin 90

A +B= 90

cos(A-B)= √3/2

cos(A-B)= cos 30

A-B=30

from 1 and 2 equation

A+B=90/A-B=30

by elimination method

2A =120

A =120/2

A=60.

by putting the value of A in equation 1st

A+B=90

60+B=90

B=90-60

B=30

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