Question

If sin(A+B)=1 and cos(A-B)=√3/2 then the value of A and B is​

Answer 1

Answer:

60degree and 30 degree..............

Answer 2

Answer:

A=60° B=30°

Step-by-step explanation:

Given sin(A+B)=1

⇒sin(A+B)=sin90 °

(∵sin90 ° =1)

⇒A+B=90 ° …………(1)

Again, cos(A−B)= 3 /2

⇒cos(A−B)=cos30 °

(∵cos30 ° = 3/2)

⇒A−B=30 °…………(2)

Adding (1)+(2)

A+B+A−B=90 °+30 °

⇒2A=120 °

⇒A=120/2

⇒A=60 °

Putting A=60 °

in equation-(2) we get

A−B=30 °

⇒60° −B=30 °

⇒60°−30° =B

⇒B=30°

∴A=60°

;B=30°

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