Question

If sin(A+B)=1 and cos(A-B)=√3÷2 Where A and B are positive acute angles with A>B,thenA and B are​

Answer 1

Step-by-step explanation:

sin(a+b)=1

then, sin (a+ b)= sin 90  (sin 90 = 1)

a+b = 90

b=90-a (i)

cos (a-b) = √3÷2

cos (a-b) = cos 30

a-b = 30

a -(90 - a) = 30 (from i)

a - 90 + a = 30

2a - 90 = 30

2a = 30 + 90

2a = 120

a= 60 (ii)

from i and ii

b=90 - 60

b=30

a=60 , b= 30

Answer 2

Answer:

given values for sin and cos are specific trigonometric ratio...substitute there value and proceed.