Question

if sin (A+B)=1 and cos (A-B) find A and B​

Answer 1

sin ( A + B ) = 1

sin ( A + B ) = sin 90

A + B = 90 ---- eq 1

Cos ( A - B ) = ✓3/2

cos ( A - B ) = cos 30

A - B = 30 ----- eq 2

from eq 1 and 2 using elemination method

A + B = 90

A - B = 30

----------------

2A = 120

A = 60 ------ eq 3

put eq 3 in eq 2

60 - B = 30

B = 30

Answer 2

Step-by-step explanation:

sin(A+B)=1

cos(A-B)=√3/2

sin90°=1

cos30°=√3/2

so

sin (A+B)=90

sin (A-B)=60

=2A=30

=A=15

Substitute A=15 in equation 1

A+B=90

then

15+B=90

B=90-15=75

Hope it helps

if u have any doubts u can ask me without hesitation

please mark me as brainliest