Question

If sin(a+b)=1 and cos(a-b)=root 3 by 2 0°b then find a and b

Answer 1

Step-by-step explanation:

Sin(A+B)=1

cos(A-B)=√3/2

We know sin-¹ =90

A+B=9 _ _ _ _(1)

cos (A-B)=root 3/2

A-B=cos-¹ root 3/2

We know cos-¹ root 3/2=30

A-B=30 _ _ _ _ _ (2)

Solve (1) & (2)

A+B=90

A-B=30 add

2A=120

A=60 B=30 (Ans)