Question

if sin (a + b )= 1 and Cos (a -b) = root 3 upon 2, wear a and b both are acute angles then find the value of a and b​

Answer 1

Answer:

Sin(A+B) =1 which is equal to 90 degree,

Cos(A-B) =root 3/2 which is equal to 30 degree

Then A+B=90

A-B=30

B GETS CUT THEN 2A=120

A=60

PUT IN 1

A+B=90

60+B=90

B=30

Answer 2

Answer:

Step-by-step explanation:

Sin(a+b)=1=Sin 90

=>a+b=90 ---- (i)

Cos(a-b)=√3/2=Cos 30

=>a-b=30 ---- (II)

Now, (i) +(II)

2a=120

=>a=60

Putting the value of a in (i),

(i) => 60+b=90

=> b=30

Hope it helps you....