Math, asked by narendrakolkata, 1 year ago


If sin(A+B) =1 and cos(A-B)=route3/2 find A and B​

Answers

Answered by dharapartha104
1

Answer:

sin (A + B)=1= son 90°

or, A + B= 90°.....(.1)

cos(A-B)=√3/2=cos30°

or, A-B=30°

or,90°-B-B=30

or, 2B= 60

B=30°.......

so,,,, A is equals to 60°.......

Hope it helps......

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