If Sin (A+B=1) and cos B =1/2 find LA, LB (0°
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Answered by
0
Answer:
sin(a+b) = 1
=> a + b = π/2 = 90°
cos b = 1/2
=> b = π/3 = 60°
=> L a = π/6 = 30°
=> L b = π/3 = 60°
Answered by
1
Answer:
∠A=30°, ∠B=60°
Step-by-step explanation:
sin(A+B) = 1
sin 90° = 1
∴ (A+B) = 90°,-----(1)
cos B = 1/2
cos 60° = 1/2
∴ B=60°
substitute B=60° in (1)
=} A+B=90°
=}A+(60°)=90°
=}A=90°-60°
=}A=30°
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