Math, asked by koushi46, 1 year ago

if sin (a+b)=1 and sin (a-b)=½,0≤a+b=90° and a>b then find a and b.

Answers

Answered by Anonymous
2

 \sin(a + b)  = 1 \\ sin90 = 1 \\  \sin(a + b)  =  \sin(90 \\ a + b = 90 \\  \sin(a - b)  = 0.5 \\ sin30 = 0.5 \\ a - b = 30 \\ 2a = 120 \\ a = 60 \\ b = 30
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